5y+y^2=336

Solution for 5y+y^2=336 equation:

5y+y^2=336

We move all terms to the left:

5y+y^2-(336)=0

a = 1; b = 5; c = -336;
Δ = b2-4ac
Δ = 52-4·1·(-336)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*1}=\frac{-42}{2}
=-21
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*1}=\frac{32}{2}
=16
$